There’s no magic to determining the duration @.050 if you have a degree wheel and a dial indicator you can set up to read off the lifter or pushrod.
Since in this case its a single pattern cam you only need to do one lobe.
Doing an intake lobe, after setting up your indicator to read directly off the lifter or pushrod, rotate the motor until the lifter is on the base circle of cam...... zero out indicator.......turn engine clockwise until you see .050” lifter rise.
See how many degrees before or after TDC that point is. Write it down.
Keep turning clockwise up and over the nose of the lobe until you are back to .050 before the base circle.
See how many degrees you are before or after BDC. Write it down.
For the opening side of the cam, anything before TDC is a +, anything after is a -.
On the closing side, anything before BDC is a -, anything after is a +.
One note here, unless the cam is very short duration, it will almost always have a closing point ABDC(@.050), but with the smaller hot street cams it’s not that unusual to have the opening point be ATDC.
Take the opening and closing points, add together, and add 180.
That’s the duration...... at whatever tappet lift you used(.006, .050, .100, etc).
For this particular excersize(determining duration at a given lift), having the cam properly degreed in isn’t necessary.
If all I’m doing is measuring the cam, I put the cam in dot to dot, eyeball TDC, and line up the pointer with the zero on the wheel and start taking readings.
In this example, a cam with
[email protected], that just happened to be installed @110 c/l, the numbers would be:
IO@ 11BTDC
IC@ 51ABDC
11 + 51 + 180 = 242
However, if it was a cam that was like
[email protected], also in at 110 it would be:
IO@ 4
ATDC
IC@ 36ABDC
-4 + 36 + 180 = 212
If you took the time to properly zero out the pointer on the degree wheel before measuring(not necessary for determining the duration @.xx lift), you would also be able to use those numbers to determine the theoretical lobe c/l, as it’s installed at that point.
Using the 242* example.......
242/2 = 121, minus the IO point of 11 = 110*
Using the 212* example......
212/2 = 106, and since the IO point of -4 is on the other side of TDC, you now have to add it back in, which puts it at 110*.